What is the value of \( 8^0 \)?

The value of ( 8^0 ) is 1 based on the mathematical property of exponents. According to the rules of exponents, any non-zero number raised to the power of zero is equal to 1. This is a fundamental concept in mathematics that applies universally across all non-zero bases.

To understand why this is the case, consider the definition of exponents. If we take a number, such as 8, and raise it to higher powers, we get ( 8^1 = 8 ), ( 8^2 = 8 \times 8 = 64 ), and so forth. If we move to lower powers, we see that ( 8^1 ) divided by ( 8^1 ) results in ( 8^{1-1} = 8^0 ). Since any number divided by itself (as long as it is not zero) equals 1, it follows that ( 8^0 = 1 ).

Thus, the correct answer is that ( 8^0 ) yields a value of 1. This aligns with the established rule for exponents and confirms that even when the base is not 1 or -1, the